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-0.005x^2+2.6x-180=0
a = -0.005; b = 2.6; c = -180;
Δ = b2-4ac
Δ = 2.62-4·(-0.005)·(-180)
Δ = 3.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6)-\sqrt{3.16}}{2*-0.005}=\frac{-2.6-\sqrt{3.16}}{-0.01} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6)+\sqrt{3.16}}{2*-0.005}=\frac{-2.6+\sqrt{3.16}}{-0.01} $
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